coderz.py

A Matrix Multiplication program is provided below.

Only when the number of columns in the first matrix equals the number of rows in the second matrix can two matrices with the same order be multiplied.

#include<stdio.h>

int main()
{
    int n, m, c, d, p, q, k, first[10][10], second[10][10], pro[10][10],sum = 0;

    printf("\nEnter the number of rows and columns of the first matrix: \n\n");
    scanf("%d%d", &m, &n);

    printf("\nEnter the %d elements of the first matrix: \n\n", m*n);
    for(c = 0; c < m; c++)   // to iterate the rows
        for(d = 0; d < n; d++)   // to iterate the columns
            scanf("%d", &first[c][d]);

    printf("\nEnter the number of rows and columns of the first matrix: \n\n");
    scanf("%d%d", &p, &q);

    if(n != p)
        printf("Matrices with the given order cannot be multiplied with each other.\n\n");

    else    
    {
        printf("\nEnter the %d elements of the second matrix: \n\n",m*n);

        for(c = 0; c < p; c++)   // to iterate the rows
            for(d = 0; d < q; d++)   // to iterate the columns
                scanf("%d", &second[c][d]);

        // printing the first matrix
        printf("\n\nThe first matrix is: \n\n");
        for(c = 0; c < m; c++)   // to iterate the rows
        {
            for(d = 0; d < n; d++)   // to iterate the columns
            {
                printf("%d\t", first[c][d]);
            }
            printf("\n");
        }

        // printing the second matrix
        printf("\n\nThe second matrix is: \n\n");
        for(c = 0; c < p; c++)   // to iterate the rows
        {
            for(d = 0; d < q; d++)   // to iterate the columns
            {
                printf("%d\t", second[c][d]);
            }
            printf("\n");
        }

        for(c = 0; c < m; c++)   // to iterate the rows
        {
            for(d = 0; d < q; d++)   // to iterate the columns
            {
                for(k = 0; k < p; k++)
                {
                    sum = sum + first[c][k]*second[k][d];
                }
            pro[c][d] = sum;    // resultant element of pro after multiplication
            sum = 0;    // to find the next element from scratch
            }
        }

        // printing the elements of the product matrix
        printf("\n\nThe multiplication of the two entered matrices is: \n\n");
        for(c = 0; c < m; c++)   // to iterate the rows
        {
            for(d = 0; d < q; d++)   // to iterate the columns
            {
                printf("%d\t", pro[c][d]);
            }
            printf("\n"); // to take the control to the next row
        }
    }
   
    return 0;
}

Output:

Enter the number of rows and columns of the first matrix: 

2 2
Enter the 4 elements of the first matrix: 

1 2 3 4
Enter the number of rows and columns of the first matrix: 

2 2 
Enter the 4 elements of the second matrix: 

9 8 7 6
The first matrix is: 

1 2 
3 4 


The second matrix is: 

9 8 
7 6 


The multiplication of the two entered matrices is: 

23 20 
55 48 

Note: also read about the Miscellaneous Program(Remove Duplicate Elements)

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