When an array contains the same number of elements in both sorted and unsorted order, the elements of the array are referred to as duplicate elements. And we must remove duplicate elements or elements with the same number from an array in order for the resultant array to contain only unique elements.
There is an integer type array arr[10] that contains 5, 8, 3, 3, 5, 9 elements, for example. 3 and 5 appear twice in this array. As a result, these elements are duplicates. We get 5, 8, 3,9 elements after removing duplicate elements from an array arr[].
Let us look at the code:
#include <stdio.h>
int main ()
{
// declare local variables
int arr[20], i, j, k, size;
printf (" Define the number of elements in an array: ");
scanf (" %d", &size);
printf (" \n Enter %d elements of an array: \n ", size);
// use for loop to enter the elements one by one in an array
for ( i = 0; i < size; i++)
{
scanf (" %d", &arr[i]);
}
// use nested for loop to find the duplicate elements in array
for ( i = 0; i < size; i ++)
{
for ( j = i + 1; j < size; j++)
{
// use if statement to check duplicate element
if ( arr[i] == arr[j])
{
// delete the current position of the duplicate element
for ( k = j; k < size - 1; k++)
{
arr[k] = arr [k + 1];
}
// decrease the size of array after removing duplicate element
size--;
// if the position of the elements is changes, don't increase the index j
j--;
}
}
}
/* display an array after deletion or removing of the duplicate elements */
printf (" \n Array elements after deletion of the duplicate elements: ");
// for loop to print the array
for ( i = 0; i < size; i++)
{
printf (" %d \t", arr[i]);
}
return 0;
}
Output:
Define the number of elements in an array: 4
Enter 4 elements of an array:
1 1 2 2
Array elements after deletion of the duplicate elements: 1 2
Note: also read about the Miscellaneous Program(Palindrome Number)
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Staying up to the mark is what defines me. Hi all! I’m Rabecca Fatima a keen learner, great enthusiast, ready to take new challenges as stepping stones towards flying colors.
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