Categories: C++

Sum Of Series 1 + 2 + 4 + 8 + 16 + 32 + . . n

Program code:

#include <iostream>
#include <math.h>
using namespace std;
//calculating the sum of the series
double calc_sum(int n) 
{
   int i;
   double sum = 0.0;
  for(i=0;i<n;++i)
    sum+=pow(2,i);

   return sum;
}
int main() 
{
   int n;
    cout<<"Enter the value of n :";
    cin>>n;
   double res = calc_sum(n);
   cout << res << endl;
   return 0;
}
Output:
Enter the value of n :5
31

Main Logic used here:

for(i=0;i<n;++i)
    sum+=pow(2,i);

Note: also read about Sum Of Series 1 + 2 + 3 + 4 + 5 + 6 . . . . n

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