To determine whether an integer number is even or odd, utilize functions.

• We have created a function even_odd(int n) with the return type is int and has parameter n.
• The parameter n is tested to see if it is divisible by two.
• If the condition is true, then n will be an even number; otherwise, it will be an odd number.
• We declared two variables in the main function: n and flag. n holds user input, while the flag stores the result returned by the method even_odd().
• The even_odd function evaluates the input n.

#include<stdio.h>  
int even_odd(int);  
void main()  
{  
 int n,flag=0;  
 printf("\n to check whether a number is even or odd");  
 printf("\nEnter the number: ");  
 scanf("%d",&n);  
 flag = even_odd(n);  
 if(flag == 0)  
 {  
    printf("\nThe number is odd");  
 }  
 else   
 {  
    printf("\nThe number is even");  
 }  
}  
int even_odd(int n)  
{  
    if(n%2 == 0)  
    {  
        return 1;  
    }  
    else   
    {  
        return 0;  
    }  
}  

output:

to check whether a number is even or odd
Enter the number: 23
The number is odd

to check whether a number is even or odd
Enter the number: 22
The number is even

Note: also read about the Recursive function in C & Call by Value & Call by Reference

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Rabecca Fatima

Staying up to the mark is what defines me. Hi all! I’m Rabecca Fatima a keen learner, great enthusiast, ready to take new challenges as stepping stones towards flying colors.