A program to compute the sum of a given series 1 + 1/2^2 + 1/3^3 + …..+ 1/n^n.
For this, we will be given the value of n, and our task will be to add up each term, beginning with the first, to find the sum of the given series.
Program code:
#include <iostream>
#include <math.h>
using namespace std;
//calculating the sum of the series
double calc_sum(int n)
{
int i;
double sum = 0.0;
for (i = 1; i <= n; i++)
sum += 1/ pow(i, i);
return sum;
}
int main()
{
int n;
cout<<"Enter the value of n : ";
cin>>n;
double res = calc_sum(n);
cout << res << endl;
return 0;
}
Output:
Enter the value of n : 5
1.29126
Note: also read about Sum Of Series 1 + 2 + 3 + 4 + 5 + 6 . . . . n
Follow Me
Please follow me to read my latest post on programming and technology if you like my post.
https://www.instagram.com/coderz.py/
https://www.facebook.com/coderz.py
Staying up to the mark is what defines me. Hi all! I’m Rabecca Fatima a keen learner, great enthusiast, ready to take new challenges as stepping stones towards flying colors.
Leave a Comment