Sum Of Series 1 + 2 + 3 + 4 + 5 + 6 . . . . n

The sum of a series consisting of n terms beginning with “1,” is equivalent to the sum of n natural numbers beginning with 1. There are numerous approaches to solving the same problem, but the ones listed below are the most commonly used by coders.

Program code:

#include<iostream>
using namespace std;
int sumseries(int num)
{
    int sum=0;
    sum=num*(num+1)/2;
    return sum;
}

int main()
{
    int n;
    cout<<"Enter the value of n : ";
    cin>>n;
    cout<<sumseries(n);
    return 0;
}

Output:

Enter the value of n : 6
21

As one can see in the above code, we directly used the formula for the sum of ‘n’ natural numbers.

Note: also read about Program to Find ASCII Value of a Character

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