Find the grade of the student based on the marks obtained in five subjects.
Let the grade be calculated based on the following pattern:
Average Mark Range | Grade |
---|---|
91-100 | A1 |
81-90 | A2 |
71-80 | B1 |
61-70 | B2 |
51-60 | C1 |
41-50 | C2 |
33-40 | D |
21-32 | E1 |
0-20 | E2 |
To calculate a student’s grade based on total marks in C++ programming, you must ask the user to enter marks from five subjects. Add the marks from all five subjects and divide by five to get the average. And then, using the table above, calculate the grade based on the average mark:
Program Code:
#include<iostream>
using namespace std;
int main()
{
int i;
float mark, sum=0, avg;
cout<<"Enter Marks obtained in 5 Subjects: ";
for(i=0; i<5; i++)
{
cin>>mark;
sum = sum+mark;
}
avg = sum/5;
cout<<"\nGrade = ";
if(avg>=91 && avg<=100)
cout<<"A1";
else if(avg>=81 && avg<91)
cout<<"A2";
else if(avg>=71 && avg<81)
cout<<"B1";
else if(avg>=61 && avg<71)
cout<<"B2";
else if(avg>=51 && avg<61)
cout<<"C1";
else if(avg>=41 && avg<51)
cout<<"C2";
else if(avg>=33 && avg<41)
cout<<"D";
else if(avg>=21 && avg<33)
cout<<"E1";
else if(avg>=0 && avg<21)
cout<<"E2";
else
cout<<"Invalid!";
cout<<endl;
return 0;
}
Output:
Enter Marks obtained in 5 Subjects:
23
78
99
56
44
Grade = C2
Note: also read about Swap Two Numbers Without Using Third Variable
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Staying up to the mark is what defines me. Hi all! I’m Rabecca Fatima a keen learner, great enthusiast, ready to take new challenges as stepping stones towards flying colors.
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