Swap Two Numbers Without Using Third Variable

By using the + and – operators, we can swap two numbers without using a third variable.

Main logic:

//Logic for swapping eg a=10, b=5
a = a + b; // a=15
b = a - b; // b=10
a = a - b; //a=5

Program code:

#include <iostream>
using namespace std;

int main()
{
    int a,b;
    cout << "Enter the first number : ";
    cin >> a;

    cout << "Enter the second number : ";
    cin >> b;

    cout << "\n\nValues Before Swapping:  \n"<<endl;
    cout << "First Number = " << a <<endl;
    cout << "Second Number = " << b <<endl;
    a = a + b;
    b = a - b;
    a = a - b;

    cout << "\n\nValues After Swapping:  \n"<<endl;

    cout << "First Number = " << a <<endl;
    cout << "Second Number = " << b <<endl;
    cout << "\n\n\n";

    return 0;
}

Output:

Enter the first number : 45
Enter the second number : 34
Values Before Swapping:  

First Number = 45
Second Number = 34


Values After Swapping:  

First Number = 34
Second Number = 45

Note: also read about Check for palindrome number

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