A palindrome number is a number that remains the same when digits are reversed. For example, the number 125521 is a palindrome number, but 1451 is not.
Program Logic:
- First, Declare a variable reverseNum and initialize it with 0.
- Now, make a while loop till the original number is greater than zero.
- In every loop, get the last digit of the number and add that digit at the end of the reverseNum and then, divide the original number by 10.
reverseNum = reverseNum * 10 + (number % 10)
- Lastly, check if the original number and reverseNum number are equal or not.
Program code:
#include<bits/stdc++.h>
using namespace std;
void check_palin(int n){
int temp=n;
int reverseNum=0;
do
{
int r = temp % 10;
reverseNum = (reverseNum * 10) + r;
temp = temp / 10;
} while (temp != 0);
if(n==reverseNum){
cout<<n<<" is a palindrome number";
}
else{
cout<<n<<" is not a palindrome number";
}
}
int main(){
int num;
cout<<"Enter the number: ";
cin>>num;
check_palin(num);
return 0;
}
Output:
Enter the number: 112232211
112232211 is a palindrome number
Note: also read about Check for Prime number
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Staying up to the mark is what defines me. Hi all! I’m Rabecca Fatima a keen learner, great enthusiast, ready to take new challenges as stepping stones towards flying colors.
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