Find Max Number Among the Given Three Number Using If/Else Statements

• n1 is compared to n2. If n1 is larger than n2, it is compared to n3. If it is greater than n3 as well, n1 is the max number; otherwise, n3 is the max number.
• If n1 is not greater than n2, it follows that n2 is greater than n1. After that, n2 is compared to n3. If it is greater than n3, n2 is the largest number; otherwise, n3 is the largest number.

Program code:

#include <iostream>
using namespace std;

int main() {
    float n1, n2, n3;

    cout << "Enter three numbers: ";
    cin >> n1 >> n2 >> n3;

    if((n1 >= n2) && (n1 >= n3))
        cout << "Largest number: " << n1;
    else if ((n2 >= n1) && (n2 >= n3))
        cout << "Largest number: " << n2;
    else
        cout << "Largest number: " << n3;
    
    return 0;
}

Output:

Enter three numbers: 55 67 43
Largest number: 67

Note: also read about Check for Prime number

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