coderz.py

Find the grade of the student based on the marks obtained in five subjects.

Let the grade be calculated based on the following pattern:

Average Mark Range	Grade
91-100	A1
81-90	A2
71-80	B1
61-70	B2
51-60	C1
41-50	C2
33-40	D
21-32	E1
0-20	E2

To calculate a student’s grade based on total marks in C++ programming, you must ask the user to enter marks from five subjects. Add the marks from all five subjects and divide by five to get the average. And then, using the table above, calculate the grade based on the average mark:

Program Code:

#include<iostream>
using namespace std;
int main()
{
    int i;
    float mark, sum=0, avg;
    cout<<"Enter Marks obtained in 5 Subjects: ";
    for(i=0; i<5; i++)
    {
        cin>>mark;
        sum = sum+mark;
    }
    avg = sum/5;
    cout<<"\nGrade = ";
    if(avg>=91 && avg<=100)
        cout<<"A1";
    else if(avg>=81 && avg<91)
        cout<<"A2";
    else if(avg>=71 && avg<81)
        cout<<"B1";
    else if(avg>=61 && avg<71)
        cout<<"B2";
    else if(avg>=51 && avg<61)
        cout<<"C1";
    else if(avg>=41 && avg<51)
        cout<<"C2";
    else if(avg>=33 && avg<41)
        cout<<"D";
    else if(avg>=21 && avg<33)
        cout<<"E1";
    else if(avg>=0 && avg<21)
        cout<<"E2";
    else
        cout<<"Invalid!";
    cout<<endl;
    return 0;
}

Output:

Enter Marks obtained in 5 Subjects: 
23
78
99
56
44
Grade = C2

Note: also read about Swap Two Numbers Without Using Third Variable

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